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Streams of water from two tanks impinge upon each other as shown in Fig. P3.36. If viscous effects are negligible and point A is a stagnation point, determine the height h. Step 1: Develop an equation that expresses how the radius changes over time and calculate the length of the radius at 3 seconds. Step 2: Apply conservation of angular momentum to calculate the car's velocity in the tangential direction at 3 seconds. Step 3: Since the car's velocity in the normal direction is already given as 0.5 ft/s we can calculate the magnitude of the car's velocity. ANS = 4.6 ft/s
Part A Step 1: Determine the radius of Mohr's circle. Step 2: Determine the distance between the origin and the center of Mohr's circle Step 3: Calculate the angle of friction. Part B Calculate angle of the failure plane. Part C Step 1: Calculate alpha. Step 2: Calculate the shear stress on the failure plane. Step 3: Calculate the normal stress on the failure plane. ANS
A) 22.02 degrees B) 56.01 degrees C) shear stress: 48.1 psi normal stress: 19.5 psi In a consolidated-drained triaxial test on a normally consolidated clay, the specimen failed at a deviator stress of 27 psi. If the effective friction angle is known to be 23 degrees, what was the effective confining pressure at failure? Solution The specimen failed in shear at 27 psi. ANS = 63.6 psi
Results of a standard Proctor compaction test on a silty sand are shown in the figure below. A) Find the maximum dry unit weight and optimum moisture content. B) What is the moist unit weight at optimum moisture content? C) What is the degree of saturation at optimum moisture content? Given: Gs=2.69. D) If the required field dry unit weight is 18.5 kN/m^(3) what is the relative compaction? E) What should be the range of compaction moisture contents in the field to achieve the above relative compaction? F) If the minimum and maximum void ratios are 0.31 and 0.82, respectively, what is the relative density of compaction in the field? Part A The maximum dry unit weight and optimum moisture content occurs at the peak of the graph. The maximum dry unit weight is roughly 19 kN/m^(3) and the optimum moisture content is around 11% Part B Use one of the derived equations to calculate the moist unit weight. Part C First calculate the void ratio. Then use one of the derived equations to calculate the degree of saturation. Part D Relative compaction: Part E First, we must find the unit weight that will allow us to achieve a 97% relative compaction. 97% of 18.5 kN/m^(3) is about 18 kN/m^(3). Therefore, the moisture content range is where 18 kN/m^(3) is achieved. The range is between 8.5% and 13%. Part F Relative density: ANS
A) maximum dry unit weight: 19 kN/m^(3) optimum moisture content: 11% B) moist unit weight: 21.09 kN/m^(3) C) S=76.09% D) RC=97.37% E) 8.5% to 13% F) Dr=0.85 |
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January 2023
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